32 lines
820 B
Python
32 lines
820 B
Python
|
"""
|
|||
|
|
获取当前登录微信的用户名称
|
|||
|
|
"""
|
|||
|
|
from wxauto import WeChat
|
|||
|
|
|
|||
|
|
def get_current_wechat_user():
|
|||
|
|
"""获取当前登录微信的用户名称
|
|||
|
|
|
|||
|
|
Returns:
|
|||
|
|
str: 当前登录微信的用户名称，如果获取失败则返回None
|
|||
|
|
"""
|
|||
|
|
try:
|
|||
|
|
# 初始化微信实例
|
|||
|
|
wx = WeChat()
|
|||
|
|
|
|||
|
|
# 获取当前登录用户的昵称
|
|||
|
|
username = wx.nickname
|
|||
|
|
|
|||
|
|
print(f"当前登录的微信用户: {username}")
|
|||
|
|
return username
|
|||
|
|
|
|||
|
|
except Exception as e:
|
|||
|
|
print(f"获取微信用户名称失败: {e}")
|
|||
|
|
return None
|
|||
|
|
|
|||
|
|
if __name__ == "__main__":
|
|||
|
|
user = get_current_wechat_user()
|
|||
|
|
if user:
|
|||
|
|
print(f"\n成功获取用户名称: {user}")
|
|||
|
|
else:
|
|||
|
|
print("\n获取用户名称失败，请确保微信已登录")
|