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ks-app-employment-service/node_modules/sm-crypto/src/sm2/sm3.js

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JavaScript
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2025-10-31 17:48:31 +08:00
// 消息扩展
const W = new Uint32Array(68)
const M = new Uint32Array(64) // W'
/**
* 循环左移
*/
function rotl(x, n) {
const s = n & 31
return (x << s) | (x >>> (32 - s))
}
/**
* 二进制异或运算
*/
function xor(x, y) {
const result = []
for (let i = x.length - 1; i >= 0; i--) result[i] = (x[i] ^ y[i]) & 0xff
return result
}
/**
* 压缩函数中的置换函数 P0(X) = X xor (X <<< 9) xor (X <<< 17)
*/
function P0(X) {
return (X ^ rotl(X, 9)) ^ rotl(X, 17)
}
/**
* 消息扩展中的置换函数 P1(X) = X xor (X <<< 15) xor (X <<< 23)
*/
function P1(X) {
return (X ^ rotl(X, 15)) ^ rotl(X, 23)
}
/**
* sm3 本体
*/
function sm3(array) {
let len = array.length * 8
// k 是满足 len + 1 + k = 448mod512 的最小的非负整数
let k = len % 512
// 如果 448 <= (512 % len) < 512需要多补充 (len % 448) 比特'0'以满足总比特长度为512的倍数
k = k >= 448 ? 512 - (k % 448) - 1 : 448 - k - 1
// 填充
const kArr = new Array((k - 7) / 8)
const lenArr = new Array(8)
for (let i = 0, len = kArr.length; i < len; i++) kArr[i] = 0
for (let i = 0, len = lenArr.length; i < len; i++) lenArr[i] = 0
len = len.toString(2)
for (let i = 7; i >= 0; i--) {
if (len.length > 8) {
const start = len.length - 8
lenArr[i] = parseInt(len.substr(start), 2)
len = len.substr(0, start)
} else if (len.length > 0) {
lenArr[i] = parseInt(len, 2)
len = ''
}
}
const m = new Uint8Array([...array, 0x80, ...kArr, ...lenArr])
const dataView = new DataView(m.buffer, 0)
// 迭代压缩
const n = m.length / 64
const V = new Uint32Array([0x7380166f, 0x4914b2b9, 0x172442d7, 0xda8a0600, 0xa96f30bc, 0x163138aa, 0xe38dee4d, 0xb0fb0e4e])
for (let i = 0; i < n; i++) {
W.fill(0)
M.fill(0)
// 将消息分组B划分为 16 个字 W0 W1……W15
const start = 16 * i
for (let j = 0; j < 16; j++) {
W[j] = dataView.getUint32((start + j) * 4, false)
}
// W16 W67W[j] <- P1(W[j16] xor W[j9] xor (W[j3] <<< 15)) xor (W[j13] <<< 7) xor W[j6]
for (let j = 16; j < 68; j++) {
W[j] = (P1((W[j - 16] ^ W[j - 9]) ^ rotl(W[j - 3], 15)) ^ rotl(W[j - 13], 7)) ^ W[j - 6]
}
// W0 W63W[j] = W[j] xor W[j+4]
for (let j = 0; j < 64; j++) {
M[j] = W[j] ^ W[j + 4]
}
// 压缩
const T1 = 0x79cc4519
const T2 = 0x7a879d8a
// 字寄存器
let A = V[0]
let B = V[1]
let C = V[2]
let D = V[3]
let E = V[4]
let F = V[5]
let G = V[6]
let H = V[7]
// 中间变量
let SS1
let SS2
let TT1
let TT2
let T
for (let j = 0; j < 64; j++) {
T = j >= 0 && j <= 15 ? T1 : T2
SS1 = rotl(rotl(A, 12) + E + rotl(T, j), 7)
SS2 = SS1 ^ rotl(A, 12)
TT1 = (j >= 0 && j <= 15 ? ((A ^ B) ^ C) : (((A & B) | (A & C)) | (B & C))) + D + SS2 + M[j]
TT2 = (j >= 0 && j <= 15 ? ((E ^ F) ^ G) : ((E & F) | ((~E) & G))) + H + SS1 + W[j]
D = C
C = rotl(B, 9)
B = A
A = TT1
H = G
G = rotl(F, 19)
F = E
E = P0(TT2)
}
V[0] ^= A
V[1] ^= B
V[2] ^= C
V[3] ^= D
V[4] ^= E
V[5] ^= F
V[6] ^= G
V[7] ^= H
}
// 转回 uint8
const result = []
for (let i = 0, len = V.length; i < len; i++) {
const word = V[i]
result.push((word & 0xff000000) >>> 24, (word & 0xff0000) >>> 16, (word & 0xff00) >>> 8, word & 0xff)
}
return result
}
/**
* hmac 实现
*/
const blockLen = 64
const iPad = new Uint8Array(blockLen)
const oPad = new Uint8Array(blockLen)
for (let i = 0; i < blockLen; i++) {
iPad[i] = 0x36
oPad[i] = 0x5c
}
function hmac(input, key) {
// 密钥填充
if (key.length > blockLen) key = sm3(key)
while (key.length < blockLen) key.push(0)
const iPadKey = xor(key, iPad)
const oPadKey = xor(key, oPad)
const hash = sm3([...iPadKey, ...input])
return sm3([...oPadKey, ...hash])
}
module.exports = {
sm3,
hmac,
}